Chem 121 Study guides, Class notes & Summaries
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CHEM 121 Lab Report 6: Measuring Kand Shifting Chemical Equilibria
- Exam (elaborations) • 8 pages • 2023
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CHEM 121 Lab Report 6: Measuring Kand Shifting Chemical Equilibria
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CHEM 121 Lab Report 4: Reaction Chemistry
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CHEM 121 Lab Report 4: Reaction Chemistry
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CHEM 121 Lab Report 9: Inorganic Synthesis
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CHEM 121 Lab Report 9: Inorganic Synthesis
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CHEM 121 Lab Report 1 - Equipment, Safety, and Mass/Volume Measurement (Portage Learning)
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CHEM 121 Lab Report 1 - Equipment, Safety, and Mass/Volume Measurement (Portage Learning)
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CHEM 121 Lab Report 7: Acid Base Titrations
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CHEM 121 Lab Report 7: Acid Base Titrations
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CHEM 121 LAB REPORT 1 TO 10 (Equipment, Safety, and Mass/Volume Measurement | Density Determination | Quantitative and Qualitative Analysis | Reaction Chemistry | Bonding Type by Solubility, Distillation, and Spectroscopy | Equilibrium Reactions | Acid Ba
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CHEM 121 LAB REPORT 1 TO 10(Equipment, Safety, and Mass/Volume Measurement | Density Determination | Quantitative and Qualitative Analysis | Reaction Chemistry | Bonding Type by Solubility,
Distillation, and Spectroscopy | Equilibrium Reactions | Acid Base Titrations | Organic Synthesis | Inorganic Synthesis | Urinalysis) - Portage Learning
 





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CHEM 121 Exam 2 SPRING 2024 Portage learning
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Show the calculation of the molecular weight for the following two compounds, reporting 
your answer to 2 places after the decimal. 
1. Ca3(PO4)2 
2. C9H8NO4Cl 
Your Answer: 
1. 3(40.08)+2(30.97+4(16))=310.18 g/mol Ca3(PO4)2 
2. 9(12.01)+8(1.008)+14.01+4(16)+35.45 = 229.61 g/mol C9H8NO4Cl 
1. 3Ca + 2P + 8O = 310.18 
2. 9C + 8H + N + 4O + Cl = 229.61 
Question 2 
9 / 10 pts 
You may find the following resources helpful: 
Scientific Calculator 
Links to an external site. 
Periodic Table 
Equation ...
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CHEM 121 Exam 1 SPRING 2024 Portage learning
- Exam (elaborations) • 17 pages • 2024
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Complete the two problems below: 
1. Convert 845.3 to exponential form and explain your answer. 
2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 
Your Answer: 
8.453x10^2 - the decimal point was moved two places to the left - the first number was 
8 
.0000321 - the decimal point needed to be moved five spaces to the left. 
1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 
places = 8.453 x 102 
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move ...
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chemistry 121/chem 121 exam 8 practice exam questions and answers
- Exam (elaborations) • 8 pages • 2022
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chemistry 121/chem 121 exam 8 practice exam questions and answers
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LSU 2024 CHEM 1212 Chemistry Lab Midterm experiment 1 to 20 Louisiana State University
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LSU 2024 CHEM 1212 Chemistry Lab Midterm experiment 1 to 20 Louisiana State University 
Experiment 1: Physical and Chemical Properties 
Experiment 2: Classifying Reactions in the Copper Cycle 
Experiment 3: Synthesis of Copper II Saccharinate 
Experiment 4: Limiting Reagent Determination 
Experiment 5: Citric Acid in Fruit Juices 
Experiment 6: Vitamin C in Fruit Juices 
Experiment 7: Investigating Conductivities of Aqueous Solutions and Conductimetric Titration 
Experiment 8: Determining % Comp...
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