Chem 103
Chem 103
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Anatomy and Physiology
J. Gordon Betts, Peter DeSaix, Jody E. Johnson, Oksana Korol, Dean H. Kruse, Brandon Poe, James A. Wise, Mark Womble, Kelly A. Young
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CHEM 103 MODULE 1 TO 6 EXAM LATEST 2022-2023 QUESTIONS & CORRECT ANSWERS PORTAGE LEARNING|COMPLETE AGRADE
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CHEM 103 MODULE 1 TO 6 EXAM LATEST 2022-2023 
QUESTIONS & CORRECT ANSWERS PORTAGE 
LEARNING|COMPLETE AGRADE
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Chem 103 Quiz 2
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Portage Learning / CHEM 103 / Module 1 to 6 Exam answers 2023|2024 UPDATED A+ RATED
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Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
1. Convert 845.3 to exponential form and explain your answer. 
2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 
1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 
places = 0. 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. ...
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Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A|
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Exam 
CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| Exam 
CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| 
 ...
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CHEM 103 Module 2 Exam (General Chemistry) – Portage Learning WITH COMPLETE SOLUTION UPDATED 2023|2024 RATED A+
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Show the calculation of the molecular weight for the following 
compounds, reporting your answer to 2 places after the decimal. 
1. Al (SO ) 
2. C H NOBr 
2 4 3 
7 5 
1. Al (SO ) 
Al = 2 x 26.98 = 53.96 
S = 3 x 32.07 = 96.21 
O = 12 x 16.00 = 192 
2 4 3 
M2: Exam - Requires Respondus LockDown Browser + Webcam: General Chemistry I w/Lab-2021- Kozminski 
3/18 
Total Molecular Weight for Al (SO ) = 342.17 
2. C H NOBr 
C = 7 x 12.01 = 84.07 
H = 5 x 1.008 = 5.04 
N = 1 x 14.01 = 14.01 
O = 1 x 16....
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CHEM 103 Module 6 Problem Set 2023 Portage learning
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Module 6: Problem Set 
Question 1 
Define or describe: 
 (a) Amorphous solid (k) Molality 
 (b) Colligative property (l) Molarity 
 (c) Colloid (m) 
Nonelectrolyte 
 (d) Condensation (n) Phase 
 (e) Critical point (o) Strong 
electrolyte 
 (f) Critical pressure (p) Sublimation 
 (g) Crystalline solid (q) Surface tension 
 (h) Electrolyte (r) Triple point 
 (i) Fluid (s) Vapor pressure 
 (j) Ionization (t) Weak 
electrolyte 
Answer: 
(a) Amorphous solids are ones in which the particles are arrang...
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chem 103 Lab Exam 3
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chem 103 Lab Exam 3/chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem 103 Lab Exam 3chem ...
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CHEM 103 Lab Report 8 Portage learning
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Chemistry Lab Report 
Experiment #: 8 
Title: Molecular Mass 
Purpose: Estimation by freezing point depression. 
Procedure: 10.0 mL of cyclohexane is measured; this is the solvent. The cyclohexane is then transferred 
into a test tube. The test tube is fitted with a special stopper and there is a special hole that has a wire to 
help stir and is also fitted with a thermometer. The test tube is then inserted into a beaker containing a 
mixture of ice and salt, this creates a cold bath. The salt i...
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PORTAGE LEARNING CHEM 103 MODULE 4 EXAM 2023
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Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the P15 atom.
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CHEM 103 FINAL EXAM VERIFIED 100% CORRECT!!
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CHEM 103 FINAL EXAM VERIFIED 100% CORRECT!!
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Chem 103 Lab exam 7 answers
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